p^2-2000p+350000=0

Solution for p^2-2000p+350000=0 equation:

p^2-2000p+350000=0

a = 1; b = -2000; c = +350000;
Δ = b2-4ac
Δ = -20002-4·1·350000
Δ = 2600000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2600000}=\sqrt{40000*65}=\sqrt{40000}*\sqrt{65}=200\sqrt{65}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2000)-200\sqrt{65}}{2*1}=\frac{2000-200\sqrt{65}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2000)+200\sqrt{65}}{2*1}=\frac{2000+200\sqrt{65}}{2}
$